Digital logic: gates, K-maps & flip-flops worksheet with answers

Free printable Digital logic: gates, K-maps & flip-flops worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
ABCG15 nsN1: 3 nsG24 nsG35 nsF

The propagation delay of every gate is written under it. Find the worst-case propagation delay tpd from the inputs to the output F.

N1: 3 nsG1: 5 nsG2: 4 nsG3: 5 ns
tpd = ns
2.Easy
A = 1B = 0C = 0N1G1G2F

The inputs of the logic circuit are A = 1, B = 0 and C = 0. Exactly one of its gates has the output 0. Click that gate.

A = 1B = 0C = 0
  1. 1N1
  2. 2G1
  3. 3G2
3.Medium
ABCD00011110000111101111

In this Karnaugh map exactly one 1 has no neighbouring 1, so it stays a group of one cell (a full minterm of four literals) in the minimal SOP form. Neighbours across the map edges count. Click that cell.

F = Σm(0, 2, 4, 14)
  1. 1AB = 00, CD = 00
  2. 2AB = 00, CD = 01
  3. 3AB = 00, CD = 11
  4. 4AB = 00, CD = 10
  5. 5AB = 01, CD = 00
  6. 6AB = 01, CD = 01
  7. 7AB = 01, CD = 11
  8. 8AB = 01, CD = 10
  9. 9AB = 11, CD = 00
  10. 10AB = 11, CD = 01
  11. 11AB = 11, CD = 11
  12. 12AB = 11, CD = 10
  13. 13AB = 10, CD = 00
  14. 14AB = 10, CD = 01
  15. 15AB = 10, CD = 11
  16. 16AB = 10, CD = 10
4.Medium
ABCD000111100001111000011312141507160121131150140819011110

Use the Karnaugh map to find the minimal sum-of-products (SOP) form of F(A, B, C, D) = Σm(2, 3, 4, 5, 6, 9, 10, 13, 15). How many literals L does it contain in total (a primed variable counts as one literal)?

F(A, B, C, D) = Σm(2, 3, 4, 5, 6, 9, 10, 13, 15)
L =
5.Hard
TQ0​Q0​TQ1​Q1​TQ2​Q2​CLK

A 3-bit ripple (asynchronous) counter is built from flip-flops with a propagation delay of 25 ns each. All outputs must have settled before the next clock edge. Find the maximum clock frequency fmax.

n = 3tpd = 25 ns
fmax = MHz
6.Hard
TQ0​Q0​TQ1​Q1​TQ2​Q2​TQ3​Q3​CLKUP

A 4-bit binary up counter starts at 2 (decimal, Q = 0010). Which count Q (in decimal) does it show after 39 clock pulses?

Q0 = 239n = 4
Q =

Answer key

  1. 1. tpd = 12 ns
  2. 2. G1
  3. 3. AB = 11, CD = 10
  4. 4. L = 18
  5. 5. fmax = 13.33 MHz
  6. 6. Q = 9

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