The inputs of the logic circuit are A = 0, B = 1 and C = 1. Exactly one of its gates has the output 1. Click that gate.
- 1N1
- 2G1
- 3G2
- 4G3
The inputs of the logic circuit are A = 0, B = 1 and C = 1. Exactly one of its gates has the output 1. Click that gate.
The function F = ((B·C)′ + A)′ is 1 for exactly one combination of the inputs. Click that row of the truth table.
In this Karnaugh map exactly one 1 has no neighbouring 1, so it stays a group of one cell (a full minterm of four literals) in the minimal SOP form. Neighbours across the map edges count. Click that cell.
Use the Karnaugh map to find the minimal product-of-sums (POS) form of F(A, B, C, D) = Σm(1, 2, 3, 4, 5, 8, 9, 10, 11, 12, 13, 14, 15). How many sum terms (factors) N does it have?
Find the minimal SOP form of F(A, B, C, D) = Σm(3, 5, 6, 8, 10, 13, 15) + d(1, 9, 14), where d marks the don't-care conditions. How many literals L does it contain?
For F(A, B, C, D) = Σm(9, 11, 12, 15) + d(2, 7), where d marks the don't-care conditions, find the number N of essential prime implicants.
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