Diodes & transistors worksheet with answers

Free printable Diodes & transistors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
+−Vs​12 VR1​ = 2.2 kΩR2​ = 1 kΩID​ = ?

A 12 V DC source is connected through resistor R₁ = 2.2 kΩ to a node X. From node X to the source’s negative terminal there are two parallel paths: resistor R₂ = 1 kΩ, and a silicon diode with its anode at X. Use the constant-drop model with 0.7 V. Find the diode current ID in mA.

Vs = 12 VR1 = 2.2 kΩR2 = 1 kΩVD = 0.7 V
ID = mA
2.Easy
+−Vs​5 VR = 330 ΩD1​D2​I = ?

A 5 V DC source drives current through a 330 Ω resistor in series with two forward-biased silicon diodes. Use the constant-drop model with 0.7 V per conducting diode. Find the current I in mA.

Vs = 5 VR = 330 ΩVD = 0.7 V
I = mA
3.Medium
RC​ = 1 kΩβ = 200IC​ = ?RE​ = 1 kΩVCC​ = 20 VR1​ = 56 kΩR2​ = 10 kΩ

An NPN transistor with β = 200 has voltage-divider bias from VCC = 20 V: R₁ = 56 kΩ from VCC to the base and R₂ = 10 kΩ from the base to ground. The collector resistor is RC = 1 kΩ and the emitter resistor is RE = 1 kΩ. Take VBE = 0.7 V and use the Thévenin equivalent of the divider (do not neglect the base current). Find the collector current IC in mA.

VCC = 20 VR1 = 56 kΩR2 = 10 kΩRC = 1 kΩRE = 1 kΩβ = 200
IC = mA
4.Medium
+−9 VR = ?3 × 2.2 V10 mA

3 green LEDs (forward voltage 2.2 V each) are connected in series with a resistor to a 9 V supply. Find the resistance R that sets the current to 10 mA.

Vs = 9 VVF = 2.2 Vn = 3I = 10 mA
R = Ω
5.Hard
V (V)I (mA)0.6566Q = ?

A diode is modelled as 0.65 V in series with 5 Ω (it conducts above 0.65 V). It is in series with a 1000 Ω resistor across a 6 V supply. Find the operating current ID where the diode line meets the load line.

Vs = 6 VR = 1000 ΩV0 = 0.65 Vrd = 5 Ω
ID = mA
6.Hard
RC​ = 330 Ωβ = 200VCC​ = 9 V5 VRB​ = ?

An NPN transistor with β = 200 switches a 330 Ω load resistor connected between VCC = 9 V and its collector. The emitter is grounded. The base is driven from a 5 V logic output through a base resistor RB. Take VBE = 0.7 V and VCE(sat) = 0.2 V. For reliable switching, design for a base current 2 times the minimum needed for saturation. Find RB in kΩ.

VCC = 9 VRC = 330 Ωβ = 200Vin = 5 VVBE = 0.7 VVCE(sat) = 0.2 Voverdrive = 2
RB = kΩ

Answer key

  1. 1. ID = 4.436 mA
  2. 2. I = 10.91 mA
  3. 3. IC = 2.225 mA
  4. 4. R = 240 Ω
  5. 5. ID = 5.323 mA
  6. 6. RB = 16.13 kΩ

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