Diodes & transistors worksheet with answers

Free printable Diodes & transistors worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
+−Vs​9 VR1​ = 470 ΩR2​ = 3.3 kΩID​ = ?

A 9 V DC source is connected through resistor R₁ = 470 Ω to a node X. From node X to the source’s negative terminal there are two parallel paths: resistor R₂ = 3.3 kΩ, and a silicon diode with its anode at X. Use the constant-drop model with 0.7 V. Find the diode current ID in mA.

Vs = 9 VR1 = 470 ΩR2 = 3.3 kΩVD = 0.7 V
ID = mA
2.Easy
+−9 V150 Ω5.1 VIR​ = ?

A 5.1 V Zener diode is fed from 9 V through a 150 Ω resistor, with no load connected. Find the current IR in the resistor.

Vin = 9 VVZ = 5.1 VR = 150 Ω
IR = mA
3.Medium
RC​ = 2.7 kΩβ = 80IC​ = ?RE​ = 1.5 kΩVCC​ = 18 VR1​ = 39 kΩR2​ = 15 kΩ

An NPN transistor with β = 80 has voltage-divider bias from VCC = 18 V: R₁ = 39 kΩ from VCC to the base and R₂ = 15 kΩ from the base to ground. The collector resistor is RC = 2.7 kΩ and the emitter resistor is RE = 1.5 kΩ. Take VBE = 0.7 V and use the Thévenin equivalent of the divider (do not neglect the base current). Find the collector current IC in mA.

VCC = 18 VR1 = 39 kΩR2 = 15 kΩRC = 2.7 kΩRE = 1.5 kΩβ = 80
IC = mA
4.Medium
RC​ = 5.6 kΩβ = 200IC​ = ?RE​ = 1 kΩVCC​ = 18 VR1​ = 56 kΩR2​ = 8.2 kΩ

An NPN transistor with β = 200 has voltage-divider bias from VCC = 18 V: R₁ = 56 kΩ from VCC to the base and R₂ = 8.2 kΩ from the base to ground. The collector resistor is RC = 5.6 kΩ and the emitter resistor is RE = 1 kΩ. Take VBE = 0.7 V and use the Thévenin equivalent of the divider (do not neglect the base current). Find the collector current IC in mA.

VCC = 18 VR1 = 56 kΩR2 = 8.2 kΩRC = 5.6 kΩRE = 1 kΩβ = 200
IC = mA
5.Hard
RC​ = 1 kΩβ = 80VCC​ = 9 V3.3 VRB​ = ?

An NPN transistor with β = 80 switches a 1 kΩ load resistor connected between VCC = 9 V and its collector. The emitter is grounded. The base is driven from a 3.3 V logic output through a base resistor RB. Take VBE = 0.7 V and VCE(sat) = 0.2 V. Find the largest base resistor RB, in kΩ, that still drives the transistor just into saturation.

VCC = 9 VRC = 1 kΩβ = 80Vin = 3.3 VVBE = 0.7 VVCE(sat) = 0.2 V
RB = kΩ
6.Hard
RC​ = 470 Ωβ = 100VCC​ = 9 V3.3 VRB​ = ?

An NPN transistor with β = 100 switches a 470 Ω load resistor connected between VCC = 9 V and its collector. The emitter is grounded. The base is driven from a 3.3 V logic output through a base resistor RB. Take VBE = 0.7 V and VCE(sat) = 0.2 V. Find the largest base resistor RB, in kΩ, that still drives the transistor just into saturation.

VCC = 9 VRC = 470 Ωβ = 100Vin = 3.3 VVBE = 0.7 VVCE(sat) = 0.2 V
RB = kΩ

Answer key

  1. 1. ID = 17.45 mA
  2. 2. IR = 26 mA
  3. 3. IC = 2.599 mA
  4. 4. IC = 1.536 mA
  5. 5. RB = 23.64 kΩ
  6. 6. RB = 13.89 kΩ

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