Evidence-based practice statistics worksheet with answers

Free printable Evidence-based practice statistics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
01 yearN = 18 500cases: 197new cases: 52CI = ?

Practice exercise (made-up values, not clinical guidance). A town has 18 500 inhabitants. At the start of a year, 197 of them have a chronic disease. During the year, 52 more people are newly diagnosed (assume nobody moves away or dies). Find the cumulative incidence CI over the year per 1000 people at risk. Round to one decimal place.

N = 18 500existing cases = 197new cases = 52
CI = per 1000
2.Easy
01 yearN = 38 500cases: 1490new cases: 568P = ?

Practice exercise (made-up values, not clinical guidance). A town has 38 500 inhabitants. At the start of a year, 1490 of them have a chronic disease. During the year, 568 more people are newly diagnosed (assume nobody moves away or dies). Find the point prevalence P at the start of the year per 1000 inhabitants. Round to one decimal place.

N = 38 500existing cases = 1490new cases = 568
P = per 1000
3.Medium
Se84%Sp90%LR− = ?

Practice exercise (made-up values, not clinical guidance). A test has a sensitivity of 84% and a specificity of 90%. Find the negative likelihood ratio LR−. Round to two decimal places.

Se = 84%Sp = 90%
LR− =
4.Medium
eventno eventtotaltreatment111819930abcontrol66324390cd

Practice exercise (made-up values, not clinical guidance). In a randomised trial, 930 patients received a new treatment and 390 received the control treatment. The table shows how many in each group had the outcome (an unwanted event such as a stroke). Find the number needed to treat NNT to prevent one event. Round up to a whole number of patients.

treatment: 111/930control: 66/390
NNT =
5.Hard
testdisease presentdisease absenttotalpositivenegative?total10 000

Practice exercise (made-up values, not clinical guidance). 10 000 people are screened with a test of sensitivity 76% and specificity 86%. The prevalence of the disease is 27%. How many people with the disease are missed by the test (false negatives, FN)?

N = 10 000p = 27%Se = 76%Sp = 86%
FN =
6.Hard
testdisease presentdisease absenttotalpositive?negativetotal10 000

Practice exercise (made-up values, not clinical guidance). 10 000 people are screened with a test of sensitivity 75% and specificity 77%. The prevalence of the disease is 29%. How many positive results n₊ are expected in total?

N = 10 000p = 29%Se = 75%Sp = 77%
n₊ =

Answer key

  1. 1. CI = 2.8 per 1000
  2. 2. P = 38.7 per 1000
  3. 3. LR− = 0.18
  4. 4. NNT = 21
  5. 5. FN = 648
  6. 6. n₊ = 3808

Full step-by-step solutions: practise this topic on examproblems.com.