Genetics worksheet with answers

Free printable Genetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
♂ Bb♀ BbbBbB

Two Bb parents are crossed. B gives purple flowers and is dominant over b, which gives white flowers. Click the cell for an offspring that has purple flowers and is homozygous.

Bb × Bb
  1. 1b × b
  2. 2b × B
  3. 3B × b
  4. 4B × B
2.Easy
♂ Bb♀ BbBbbB

Two Bb parents are crossed. B gives yellow seeds and is dominant over b, which gives green seeds. Click the cell of the Punnett square for an offspring with green seeds.

Bb × Bb
  1. 1b × B
  2. 2b × b
  3. 3B × B
  4. 4B × b
3.Medium
AaBb ♀aabb ♂ABAbaBababababab????????????????

Tall (A) is dominant over short (a), and round seeds (B) over wrinkled (b). The genes are on different chromosomes. For the cross AaBb × aabb, what is the probability P that an offspring is tall, wrinkled seeds?

AaBb × aabb
P =
4.Medium
AaBb ♀Aabb ♂ABAbaBabAbAbabab????????????????

Tall (A) is dominant over short (a), and round seeds (B) over wrinkled (b). The genes are on different chromosomes. For the cross AaBb × Aabb, what is the probability P that an offspring is short, round seeds?

AaBb × Aabb
P =
5.Hard
♂ AaBb♀ AaBbABaBAbabAbABaBab

Two AaBb parents are crossed. Gene A gives round seeds (dominant) or wrinkled seeds; gene B gives black fur (dominant) or white fur. Click the one cell for an offspring that is shows both wrinkled seeds and white fur.

AaBb × AaBb
  1. 1Ab × AB
  2. 2Ab × aB
  3. 3Ab × Ab
  4. 4Ab × ab
  5. 5AB × AB
  6. 6AB × aB
  7. 7AB × Ab
  8. 8AB × ab
  9. 9aB × AB
  10. 10aB × aB
  11. 11aB × Ab
  12. 12aB × ab
  13. 13ab × AB
  14. 14ab × aB
  15. 15ab × Ab
  16. 16ab × ab
6.Hard
AA?AaAaaap (A)q (a)p (A)q (a)q² = 0.04N = 10000

In a population of 10000 in Hardy–Weinberg equilibrium, 4% show a recessive trait. How many individuals N are expected to be homozygous dominant?

N = 10000q² = 0.04
N =

Answer key

  1. 1. B × B
  2. 2. b × b
  3. 3. P = 0.25
  4. 4. P = 0.125
  5. 5. ab × ab
  6. 6. N = 6400

Full step-by-step solutions: practise this topic on examproblems.com.