Genetics worksheet with answers

Free printable Genetics worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
♂ Bb♀ BbbBBb

Two Bb parents are crossed. B gives black fur and is dominant over b, which gives white fur. Click the cell for an offspring that has black fur and is homozygous.

Bb × Bb
  1. 1B × b
  2. 2B × B
  3. 3b × b
  4. 4b × B
2.Easy
Aa ♀AA ♂AaAA????

In pea plants, purple flowers (A) are dominant over white (a). A plant with genotype Aa is crossed with a plant with genotype AA. What is the probability P that an offspring has purple flowers?

Aa × AA
P =
3.Medium
♂♀Xb​YXb​XB​

red-green colour blindness is X-linked recessive (allele b). A carrier mother, XBXb, has children with an affected father, XbY. The mother's gametes run down the side. Click the cell for an affected daughter.

♀ XBXb♂ XbY
  1. 1Xb × Xb
  2. 2Xb × Y
  3. 3XB × Xb
  4. 4XB × Y
4.Medium
♂♀YXB​Xb​XB​

red-green colour blindness is X-linked recessive (allele b). A carrier mother, XBXb, has children with an unaffected father, XBY. The mother's gametes run down the side. Click the cell for an unaffected son.

♀ XBXb♂ XBY
  1. 1Xb × Y
  2. 2Xb × XB
  3. 3XB × Y
  4. 4XB × XB
5.Hard
♂ AaBb♀ AaBbABaBAbababAbaBAB

Two AaBb parents are crossed. Gene A gives tall plants (dominant) or short plants; gene B gives round seeds (dominant) or wrinkled seeds. Click the one cell for an offspring that is shows short plants and is homozygous for round seeds.

AaBb × AaBb
  1. 1ab × AB
  2. 2ab × aB
  3. 3ab × Ab
  4. 4ab × ab
  5. 5Ab × AB
  6. 6Ab × aB
  7. 7Ab × Ab
  8. 8Ab × ab
  9. 9aB × AB
  10. 10aB × aB
  11. 11aB × Ab
  12. 12aB × ab
  13. 13AB × AB
  14. 14AB × aB
  15. 15AB × Ab
  16. 16AB × ab
6.Hard
AA?AaAaaap (A)q (a)p (A)q (a)q² = 0.16N = 2000

In a population of 2000 in Hardy–Weinberg equilibrium, 16% show a recessive trait. How many individuals N are expected to be homozygous dominant?

N = 2000q² = 0.16
N =

Answer key

  1. 1. B × B
  2. 2. P = 1
  3. 3. Xb × Xb
  4. 4. XB × Y
  5. 5. aB × aB
  6. 6. N = 720

Full step-by-step solutions: practise this topic on examproblems.com.