Heat engines & refrigerators worksheet with answers

Free printable Heat engines & refrigerators worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
kitchencold spaceRQ̇H​Q̇L​ = 6.96 kWẆ = 2.4 kW

A refrigerator removes heat from its cold space at a rate of 6.96 kW while its compressor uses 2.4 kW of power. Find its coefficient of performance COPR.

Q̇L = 6.96 kWẆ = 2.4 kW
COPR =
2.Easy
hot reservoircold reservoirEQH​ = 3200 kJQL​ = 1920 kJW

A heat engine takes in 3200 kJ of heat from a hot reservoir and rejects 1920 kJ to a cold reservoir in each cycle. Find its thermal efficiency η.

QH = 3200 kJQL = 1920 kJ
η = %
3.Medium
TH​ = 500 °CTL​ = 35 °CEQH​ = 1600 kJQL​W = ?

A heat engine works between a hot reservoir at 500 °C and a cold reservoir at 35 °C. It takes in 1600 kJ of heat. Find the most work Wmax it could possibly produce.

TH = 500 °CTL = 35 °CQH = 1600 kJ
Wmax = kJ
4.Medium
TH​ = 525 °CTL​ = 25 °CEQH​QL​W

A heat engine works between a hot reservoir at 525 °C and a cold reservoir at 25 °C. Find the highest possible thermal efficiency ηmax.

TH = 525 °CTL = 25 °C
ηmax = %
5.Hard
TH​ = 850 °CTL​ = 25 °CEQH​ = 2000 kJQL​ = 980 kJW = 1020 kJ

A heat engine takes in 2000 kJ of heat from a reservoir at 850 °C, produces 1020 kJ of work and rejects the rest to a reservoir at 25 °C, per cycle. Find the total entropy generated Sgen per cycle.

TH = 850 °CTL = 25 °CQH = 2000 kJW = 1020 kJ
Sgen = kJ/K
6.Hard
TH​ = 900 °CTL​ = 20 °CEQH​ = 500 kJQL​ = 310 kJW = 190 kJ

A heat engine takes in 500 kJ of heat from a reservoir at 900 °C, produces 190 kJ of work and rejects the rest to a reservoir at 20 °C, per cycle. Find the total entropy generated Sgen per cycle.

TH = 900 °CTL = 20 °CQH = 500 kJW = 190 kJ
Sgen = kJ/K

Answer key

  1. 1. COPR = 2.9
  2. 2. η = 40 %
  3. 3. Wmax = 962.3 kJ
  4. 4. ηmax = 62.64 %
  5. 5. Sgen = 1.506 kJ/K
  6. 6. Sgen = 0.6313 kJ/K

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