1.Easy
Evaluate I = ∫−12 (−3x2 − 2x − 2) dx.
f(x) = −3x2 − 2x − 2[−1, 2]
I =
Evaluate I = ∫−12 (−3x2 − 2x − 2) dx.
Evaluate I = ∫13 (3x3 + 4x + 8) dx.
Evaluate I = ∫₀1 x·sin x dx (x in radians).
Evaluate I = ∫₁2 x·ln x dx.
Find the area A of the region between the parabola y = 1 − x² and the x-axis.
Evaluate I = ∫₀2 x²·eˣ dx.
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