How many usable host addresses H are there in an IPv4 subnet with prefix /29?
IPv4 subnetting worksheet with answers
1.Easy
/29
H =
2.Easy
A subnet has the mask 255.255.240.0. What is its prefix length p?
255.255.240.0
p =
3.Medium
The network 192.168.10.0/24 must be divided into at least 3 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?
192.168.10.0/243 subnets
H =
4.Medium
The network 172.27.0.0/16 is divided into equal subnets with prefix /24. How many subnets N are there?
172.27.0.0/16/24
N =
5.Hard
A host has the address 10.20.242.100/29. What is the last number (fourth octet) x of its subnet's broadcast address?
10.20.242.100/29
x =
6.Hard
A router has routes to these networks: 10.71.158.0/24, 10.71.159.0/24, 10.71.160.0/24, 10.71.161.0/24. What is the longest prefix length p of a single summary route that covers all of them?
10.71.158.0/24 … 10.71.161.0/24
p =
Answer key
- 1. H = 6
- 2. p = 20
- 3. H = 62
- 4. N = 256
- 5. x = 103
- 6. p = 18
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