IPv4 subnetting worksheet with answers

Free printable IPv4 subnetting worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

New worksheetPractise online with hints

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
255.255.255.25211111111111111111111111111111100network bitshost bits

A subnet has the mask 255.255.255.252. What is its prefix length p?

255.255.255.252
p =
2.Easy
third octet of /23112816413211618141201oneszeros

Write the subnet mask of a /23 network in dotted-decimal notation. What is the value x of its third octet?

/23
x =
3.Medium
/24 → /2811111111111111111111111111110000network bitshost bits

The network 192.168.10.0/24 must be divided into at least 10 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?

192.168.10.0/2410 subnets
H =
4.Medium
/24 → /2711111111111111111111111111100000network bitshost bits

The network 10.132.224.0/24 is divided into equal subnets with prefix /27. How many subnets N are there?

10.132.224.0/24/27
N =
5.Hard
third octet 220 … 221112816403211618140201commonvaries

A router has routes to these networks: 10.96.220.0/24, 10.96.221.0/24. What is the longest prefix length p of a single summary route that covers all of them?

10.96.220.0/24 … 10.96.221.0/24
p =
6.Hard
last octet = 13012806403201618140211networkhost

A host has the address 10.20.163.13/26. What is the fourth octet x of the last usable host address in its subnet?

10.20.163.13/26
x =

Answer key

  1. 1. p = 30
  2. 2. x = 254
  3. 3. H = 14
  4. 4. N = 8
  5. 5. p = 23
  6. 6. x = 62

Full step-by-step solutions: practise this topic on examproblems.com.