How many usable host addresses H are there in an IPv4 subnet with prefix /25?
IPv4 subnetting worksheet with answers
1.Easy
/25
H =
2.Easy
How many usable host addresses H are there in an IPv4 subnet with prefix /24?
/24
H =
3.Medium
The network 10.10.90.0/24 is divided into equal subnets with prefix /28. How many subnets N are there?
10.10.90.0/24/28
N =
4.Medium
The network 192.168.10.0/24 must be divided into at least 5 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?
192.168.10.0/245 subnets
H =
5.Hard
A host has the address 172.20.144.9/19. What is the third octet x of its network address?
172.20.144.9/19
x =
6.Hard
A host has the address 172.20.53.26/19. What is the third octet x of its subnet's broadcast address?
172.20.53.26/19
x =
Answer key
- 1. H = 126
- 2. H = 254
- 3. N = 16
- 4. H = 30
- 5. x = 128
- 6. x = 63
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