How many usable host addresses H are there in an IPv4 subnet with prefix /25?
IPv4 subnetting worksheet with answers
1.Easy
/25
H =
2.Easy
How many usable host addresses H are there in an IPv4 subnet with prefix /24?
/24
H =
3.Medium
The network 192.168.154.0/24 is divided into /25 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the broadcast address of subnet 2?
192.168.154.0/24/25subnet 2 (subnet 1 starts at .0)
x =
4.Medium
A subnet uses the mask 255.255.255.240. How many usable host addresses H does it have?
255.255.255.240
H =
5.Hard
A host has the address 10.20.224.18/29. What is the fourth octet x of its network address?
10.20.224.18/29
x =
6.Hard
A router has routes to these networks: 10.115.179.0/24, 10.115.180.0/24, 10.115.181.0/24. What is the longest prefix length p of a single summary route that covers all of them?
10.115.179.0/24 … 10.115.181.0/24
p =
Answer key
- 1. H = 126
- 2. H = 254
- 3. x = 255
- 4. H = 14
- 5. x = 16
- 6. p = 21
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