How many usable host addresses H are there in an IPv4 subnet with prefix /21?
IPv4 subnetting worksheet with answers
1.Easy
/21
H =
2.Easy
How many usable host addresses H are there in an IPv4 subnet with prefix /24?
/24
H =
3.Medium
The network 172.21.0.0/16 is divided into equal subnets with prefix /20. How many subnets N are there?
172.21.0.0/16/20
N =
4.Medium
The network 192.168.10.0/24 must be divided into at least 30 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?
192.168.10.0/2430 subnets
H =
5.Hard
A router has routes to these networks: 10.135.74.0/24, 10.135.75.0/24, 10.135.76.0/24, 10.135.77.0/24, 10.135.78.0/24. What is the longest prefix length p of a single summary route that covers all of them?
10.135.74.0/24 … 10.135.78.0/24
p =
6.Hard
A host has the address 10.20.92.20/30. What is the last number (fourth octet) x of its subnet's broadcast address?
10.20.92.20/30
x =
Answer key
- 1. H = 2046
- 2. H = 254
- 3. N = 16
- 4. H = 6
- 5. p = 21
- 6. x = 23
Full step-by-step solutions: practise this topic on examproblems.com.