How many usable host addresses H are there in an IPv4 subnet with prefix /23?
IPv4 subnetting worksheet with answers
1.Easy
/23
H =
2.Easy
How many usable host addresses H are there in an IPv4 subnet with prefix /25?
/25
H =
3.Medium
The network 10.138.52.0/22 is divided into equal subnets with prefix /29. How many subnets N are there?
10.138.52.0/22/29
N =
4.Medium
The network 192.168.151.0/24 is divided into /27 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the network address of subnet 6?
192.168.151.0/24/27subnet 6 (subnet 1 starts at .0)
x =
5.Hard
A router has routes to these networks: 10.238.19.0/24, 10.238.20.0/24, 10.238.21.0/24. What is the longest prefix length p of a single summary route that covers all of them?
10.238.19.0/24 … 10.238.21.0/24
p =
6.Hard
A host has the address 10.20.231.80/28. What is the fourth octet x of its network address?
10.20.231.80/28
x =
Answer key
- 1. H = 510
- 2. H = 126
- 3. N = 128
- 4. x = 160
- 5. p = 21
- 6. x = 80
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