How many usable host addresses H are there in an IPv4 subnet with prefix /23?
IPv4 subnetting worksheet with answers
1.Easy
/23
H =
2.Easy
How many usable host addresses H are there in an IPv4 subnet with prefix /22?
/22
H =
3.Medium
The network 10.50.212.0/22 is divided into equal subnets with prefix /29. How many subnets N are there?
10.50.212.0/22/29
N =
4.Medium
The network 192.168.10.0/24 must be divided into at least 20 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?
192.168.10.0/2420 subnets
H =
5.Hard
A host has the address 10.20.112.164/26. What is the fourth octet x of its network address?
10.20.112.164/26
x =
6.Hard
A host has the address 10.20.171.7/26. What is the last number (fourth octet) x of its subnet's broadcast address?
10.20.171.7/26
x =
Answer key
- 1. H = 510
- 2. H = 1022
- 3. N = 128
- 4. H = 6
- 5. x = 128
- 6. x = 63
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