How many usable host addresses H are there in an IPv4 subnet with prefix /21?
IPv4 subnetting worksheet with answers
1.Easy
/21
H =
2.Easy
How many usable host addresses H are there in an IPv4 subnet with prefix /25?
/25
H =
3.Medium
A subnet uses the mask 255.255.255.128. How many usable host addresses H does it have?
255.255.255.128
H =
4.Medium
The network 192.168.99.0/24 is divided into /29 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the network address of subnet 7?
192.168.99.0/24/29subnet 7 (subnet 1 starts at .0)
x =
5.Hard
A router has routes to these networks: 10.82.52.0/24, 10.82.53.0/24, 10.82.54.0/24, 10.82.55.0/24. What is the longest prefix length p of a single summary route that covers all of them?
10.82.52.0/24 … 10.82.55.0/24
p =
6.Hard
A host has the address 10.20.46.220/27. What is the last number (fourth octet) x of its subnet's broadcast address?
10.20.46.220/27
x =
Answer key
- 1. H = 2046
- 2. H = 126
- 3. H = 126
- 4. x = 48
- 5. p = 22
- 6. x = 223
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