A subnet has the mask 255.255.192.0. What is its prefix length p?
IPv4 subnetting worksheet with answers
1.Easy
255.255.192.0
p =
2.Easy
An access list must match the network 192.168.1.0/28. Access lists use a wildcard mask, the inverse of the subnet mask. What is the fourth octet x of the wildcard mask?
/28
x =
3.Medium
The network 192.168.10.0/24 must be divided into at least 30 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?
192.168.10.0/2430 subnets
H =
4.Medium
The network 172.26.0.0/16 is divided into equal subnets with prefix /21. How many subnets N are there?
172.26.0.0/16/21
N =
5.Hard
A host has the address 10.20.132.195/26. What is the fourth octet x of the last usable host address in its subnet?
10.20.132.195/26
x =
6.Hard
A host has the address 10.20.112.65/25. What is the last number (fourth octet) x of its subnet's broadcast address?
10.20.112.65/25
x =
Answer key
- 1. p = 18
- 2. x = 15
- 3. H = 6
- 4. N = 32
- 5. x = 254
- 6. x = 127
Full step-by-step solutions: practise this topic on examproblems.com.