IPv4 subnetting worksheet with answers

Free printable IPv4 subnetting worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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Name: ____________________   Date: ____________

1.Easy
/2011111111111111111111000000000000network bitshost bits

An access list must match the network 172.16.0.0/20. Access lists use a wildcard mask, the inverse of the subnet mask. What is the third octet x of the wildcard mask?

/20
x =
2.Easy
255.255.255.12811111111111111111111111110000000network bitshost bits

A subnet has the mask 255.255.255.128. What is its prefix length p?

255.255.255.128
p =
3.Medium
/24 → /2611111111111111111111111111000000network bitshost bits

The network 192.168.96.0/24 is divided into /26 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the network address of subnet 2?

192.168.96.0/24/26subnet 2 (subnet 1 starts at .0)
x =
4.Medium
/24 → /2911111111111111111111111111111000network bitshost bits

The network 192.168.101.0/24 is divided into /29 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the broadcast address of subnet 2?

192.168.101.0/24/29subnet 2 (subnet 1 starts at .0)
x =
5.Hard

The network 192.168.97.0/24 is split with VLSM for these LANs: A: 85 hosts, B: 33 hosts, C: 20 hosts, D: 8 hosts. Subnets are allocated from .0 upwards, the LAN with the most hosts first, each with the smallest subnet that fits. What is the fourth octet x of the network address of LAN B?

A: 85B: 33C: 20D: 8
x =
6.Hard
last octet = 81012816403211608040211networkhost

A host has the address 10.20.27.81/27. What is the fourth octet x of its network address?

10.20.27.81/27
x =

Answer key

  1. 1. x = 15
  2. 2. p = 25
  3. 3. x = 64
  4. 4. x = 15
  5. 5. x = 128
  6. 6. x = 64

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