IPv4 subnetting worksheet with answers

Free printable IPv4 subnetting worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
/1811111111111111111100000000000000network bitshost bits

An access list must match the network 172.16.0.0/18. Access lists use a wildcard mask, the inverse of the subnet mask. What is the third octet x of the wildcard mask?

/18
x =
2.Easy
255.255.255.25211111111111111111111111111111100network bitshost bits

A subnet has the mask 255.255.255.252. What is its prefix length p?

255.255.255.252
p =
3.Medium
/24 → /2711111111111111111111111111100000network bitshost bits

The network 192.168.165.0/24 is divided into /27 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the network address of subnet 8?

192.168.165.0/24/27subnet 8 (subnet 1 starts at .0)
x =
4.Medium
/24 → /2711111111111111111111111111100000network bitshost bits

The network 192.168.10.0/24 must be divided into at least 6 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?

192.168.10.0/246 subnets
H =
5.Hard
third octet 167 … 171112806413201608141211commonvaries

A router has routes to these networks: 10.107.167.0/24, 10.107.168.0/24, 10.107.169.0/24, 10.107.170.0/24, 10.107.171.0/24. What is the longest prefix length p of a single summary route that covers all of them?

10.107.167.0/24 … 10.107.171.0/24
p =
6.Hard
third octet 110 … 113012816413201618141201commonvaries

A router has routes to these networks: 10.141.110.0/24, 10.141.111.0/24, 10.141.112.0/24, 10.141.113.0/24. What is the longest prefix length p of a single summary route that covers all of them?

10.141.110.0/24 … 10.141.113.0/24
p =

Answer key

  1. 1. x = 63
  2. 2. p = 30
  3. 3. x = 224
  4. 4. H = 30
  5. 5. p = 20
  6. 6. p = 19

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