How many usable host addresses H are there in an IPv4 subnet with prefix /21?
IPv4 subnetting worksheet with answers
1.Easy
/21
H =
2.Easy
How many usable host addresses H are there in an IPv4 subnet with prefix /25?
/25
H =
3.Medium
The network 172.25.0.0/16 is divided into equal subnets with prefix /20. How many subnets N are there?
172.25.0.0/16/20
N =
4.Medium
The network 192.168.166.0/24 is divided into /28 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the broadcast address of subnet 9?
192.168.166.0/24/28subnet 9 (subnet 1 starts at .0)
x =
5.Hard
A host has the address 10.20.16.188/27. What is the last number (fourth octet) x of its subnet's broadcast address?
10.20.16.188/27
x =
6.Hard
A host has the address 10.20.20.6/30. What is the last number (fourth octet) x of its subnet's broadcast address?
10.20.20.6/30
x =
Answer key
- 1. H = 2046
- 2. H = 126
- 3. N = 16
- 4. x = 143
- 5. x = 191
- 6. x = 7
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