How many usable host addresses H are there in an IPv4 subnet with prefix /24?
IPv4 subnetting worksheet with answers
1.Easy
/24
H =
2.Easy
A subnet has the mask 255.255.255.192. What is its prefix length p?
255.255.255.192
p =
3.Medium
The network 172.22.0.0/16 is divided into equal subnets with prefix /21. How many subnets N are there?
172.22.0.0/16/21
N =
4.Medium
A subnet uses the mask 255.255.255.128. How many usable host addresses H does it have?
255.255.255.128
H =
5.Hard
A host has the address 172.20.180.148/23. What is the third octet x of its subnet's broadcast address?
172.20.180.148/23
x =
6.Hard
The network 192.168.120.0/24 is split with VLSM for these LANs: A: 103 hosts, B: 18 hosts, C: 49 hosts, D: 7 hosts. Subnets are allocated from .0 upwards, the LAN with the most hosts first, each with the smallest subnet that fits. What is the fourth octet x of the network address of LAN C?
A: 103B: 18C: 49D: 7
x =
Answer key
- 1. H = 254
- 2. p = 26
- 3. N = 32
- 4. H = 126
- 5. x = 181
- 6. x = 128
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