An access list must match the network 172.16.0.0/18. Access lists use a wildcard mask, the inverse of the subnet mask. What is the third octet x of the wildcard mask?
IPv4 subnetting worksheet with answers
1.Easy
/18
x =
2.Easy
Write the subnet mask of a /19 network in dotted-decimal notation. What is the value x of its third octet?
/19
x =
3.Medium
A subnet uses the mask 255.255.248.0. How many usable host addresses H does it have?
255.255.248.0
H =
4.Medium
The network 172.27.0.0/16 is divided into equal subnets with prefix /19. How many subnets N are there?
172.27.0.0/16/19
N =
5.Hard
A router has routes to these networks: 10.8.203.0/24, 10.8.204.0/24, 10.8.205.0/24, 10.8.206.0/24, 10.8.207.0/24, 10.8.208.0/24, 10.8.209.0/24, 10.8.210.0/24. What is the longest prefix length p of a single summary route that covers all of them?
10.8.203.0/24 … 10.8.210.0/24
p =
6.Hard
A host has the address 172.20.234.26/17. What is the third octet x of its subnet's broadcast address?
172.20.234.26/17
x =
Answer key
- 1. x = 63
- 2. x = 224
- 3. H = 2046
- 4. N = 8
- 5. p = 19
- 6. x = 255
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