IPv4 subnetting worksheet with answers

Free printable IPv4 subnetting worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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Name: ____________________   Date: ____________

1.Easy
/2211111111111111111111110000000000network bitshost bits

How many usable host addresses H are there in an IPv4 subnet with prefix /22?

/22
H =
2.Easy
/2711111111111111111111111111100000network bitshost bits

How many usable host addresses H are there in an IPv4 subnet with prefix /27?

/27
H =
3.Medium
/24 → /2511111111111111111111111110000000network bitshost bits

The network 192.168.71.0/24 is divided into /25 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the network address of subnet 2?

192.168.71.0/24/25subnet 2 (subnet 1 starts at .0)
x =
4.Medium
/24 → /2511111111111111111111111110000000network bitshost bits

The network 192.168.140.0/24 is divided into /25 subnets, numbered 1, 2, 3, … from the lowest address (subnet 1 starts at .0). What is the fourth octet x of the broadcast address of subnet 2?

192.168.140.0/24/25subnet 2 (subnet 1 starts at .0)
x =
5.Hard
third octet 157 … 161112806403211618140211commonvaries

A router has routes to these networks: 10.23.157.0/24, 10.23.158.0/24, 10.23.159.0/24, 10.23.160.0/24, 10.23.161.0/24. What is the longest prefix length p of a single summary route that covers all of them?

10.23.157.0/24 … 10.23.161.0/24
p =
6.Hard
last octet = 169112806413201618040211networkhost

A host has the address 10.20.152.169/25. What is the last number (fourth octet) x of its subnet's broadcast address?

10.20.152.169/25
x =

Answer key

  1. 1. H = 1022
  2. 2. H = 30
  3. 3. x = 128
  4. 4. x = 255
  5. 5. p = 18
  6. 6. x = 255

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