Write the subnet mask of a /21 network in dotted-decimal notation. What is the value x of its third octet?
IPv4 subnetting worksheet with answers
1.Easy
/21
x =
2.Easy
An access list must match the network 192.168.1.0/25. Access lists use a wildcard mask, the inverse of the subnet mask. What is the fourth octet x of the wildcard mask?
/25
x =
3.Medium
The network 192.168.10.0/24 must be divided into at least 6 equal subnets. If you borrow as few bits as possible, how many usable hosts H does each subnet have?
192.168.10.0/246 subnets
H =
4.Medium
The network 10.122.80.0/20 is divided into equal subnets with prefix /27. How many subnets N are there?
10.122.80.0/20/27
N =
5.Hard
A host has the address 10.20.4.212/25. What is the last number (fourth octet) x of its subnet's broadcast address?
10.20.4.212/25
x =
6.Hard
A host has the address 10.20.95.189/25. What is the fourth octet x of its network address?
10.20.95.189/25
x =
Answer key
- 1. x = 248
- 2. x = 127
- 3. H = 30
- 4. N = 128
- 5. x = 255
- 6. x = 128
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