A signal f(t) has the Laplace transform F(s) = 13(s + 5)/(s(s + 1)(s + 3)). Use the final value theorem to find the value f(∞) that f(t) settles to.
Laplace transforms worksheet with answers
1.Easy
F(s) = 13(s + 5)/(s(s + 1)(s + 3))
f(∞) =
2.Easy
Find the inverse Laplace transform f(t) of F(s) = 7/(s + 2) − 9/s with a table of transform pairs, and evaluate f(0.25).
F(s) = 7/(s + 2) − 9/st = 0.25 s
f(0.25) =
3.Medium
F(s) = (5s + 17)/(s² + 12s + 35). Its inverse transform has the form f(t) = A·e−5t + B·e−7t. Find the coefficient A by partial fractions.
F(s) = (5s + 17)/(s² + 12s + 35)
A =
4.Medium
Find f(t) for F(s) = (3s + 37)/(s² + 6s + 10) by completing the square, and evaluate f(0.4).
F(s) = (3s + 37)/(s² + 6s + 10)t = 0.4 s
f(0.4) =
5.Hard
A system obeys y″ + 7y′ + 12y = 48·u(t), with y(0) = 6 and y′(0) = 0. At t = 0 a step input u(t) = 4 is applied. Use the Laplace transform to find y(0.2).
y″ + 7y′ + 12y = 48·u(t)y(0) = 6y′(0) = 0u(t) = 4t = 0.2 s
y(0.2) =
6.Hard
Solve y″ + 9y′ + 20y = 0 with y(0) = 2 and y′(0) = 11 using the Laplace transform, and find y(0.3).
y″ + 9y′ + 20y = 0y(0) = 2y′(0) = 11t = 0.3 s
y(0.3) =
Answer key
- 1. f(∞) = 21.67
- 2. f(0.25) = −4.754
- 3. A = −4
- 4. f(0.4) = 4.116
- 5. y(0.2) = 7.527
- 6. y(0.3) = 2.086
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