A signal f(t) has the Laplace transform F(s) = (3s² + 13s + 16)/(s(s + 5)(s + 6)). Use the initial value theorem to find f(0⁺), the value of f(t) just after t = 0.
Laplace transforms worksheet with answers
1.Easy
F(s) = (3s² + 13s + 16)/(s(s + 5)(s + 6))
f(0⁺) =
2.Easy
A signal f(t) has the Laplace transform F(s) = 20(s + 6)/(s(s + 5)(s + 8)). Use the final value theorem to find the value f(∞) that f(t) settles to.
F(s) = 20(s + 6)/(s(s + 5)(s + 8))
f(∞) =
3.Medium
Find f(t) for F(s) = (3s + 19)/(s² + 4s + 13) by completing the square, and evaluate f(0.3).
F(s) = (3s + 19)/(s² + 4s + 13)t = 0.3 s
f(0.3) =
4.Medium
F(s) = 18/(s² + 5s + 6). Its inverse transform has the form f(t) = A·e−2t + B·e−3t. Find the coefficient A by partial fractions.
F(s) = 18/(s² + 5s + 6)
A =
5.Hard
Solve y″ + 8y′ + 12y = 0 with y(0) = 8 and y′(0) = 3 using the Laplace transform, and find y(0.5).
y″ + 8y′ + 12y = 0y(0) = 8y′(0) = 3t = 0.5 s
y(0.5) =
6.Hard
A system obeys y″ + 4y′ + 3y = 9·u(t), with y(0) = 4 and y′(0) = 0. At t = 0 a step input u(t) = 4 is applied. Use the Laplace transform to find y(0.25).
y″ + 4y′ + 3y = 9·u(t)y(0) = 4y′(0) = 0u(t) = 4t = 0.25 s
y(0.25) =
Answer key
- 1. f(0⁺) = 3
- 2. f(∞) = 3
- 3. f(0.3) = 2.886
- 4. A = 18
- 5. y(0.5) = 4.454
- 6. y(0.25) = 4.544
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