A resonance curve peaks at 500 kHz, and its half-power points are 6.25 kHz apart. Find the quality factor Q.
LC resonance, Q factor & bandwidth worksheet with answers
1.Easy
f0 = 500 kHzBW = 6.25 kHz
Q =
2.Easy
An LC circuit with L = 100 mH must resonate at 20 kHz. Find the capacitance C in nF.
L = 100 mHf0 = 20 kHz
C = nF
3.Medium
A series RLC circuit has R = 10 Ω, L = 10 mH and C = 220 nF. Find its bandwidth BW in Hz.
R = 10 ΩL = 10 mHC = 220 nF
BW = Hz
4.Medium
A series RLC circuit resonates at 5 kHz with Q = 3. Find the lower half-power frequency f1 exactly, in kHz.
f0 = 5 kHzQ = 3
f1 = kHz
5.Hard
The half-power frequencies of a resonance curve are 10 kHz and 10.5 kHz. Find the resonance frequency as their geometric mean, and then the quality factor Q.
f1 = 10 kHzf2 = 10.5 kHz
Q =
6.Hard
A series resonant circuit uses a 22 µH inductor. Which total series resistance R gives a bandwidth of 1 kHz?
L = 22 µHBW = 1 kHz
R = Ω
Answer key
- 1. Q = 80
- 2. C = 0.6333 nF
- 3. BW = 159.2 Hz
- 4. f1 = 4.236 kHz
- 5. Q = 20.49
- 6. R = 0.1382 Ω
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