A resonance curve peaks at 10 kHz, and its half-power points are 100 Hz apart. Find the quality factor Q.
LC resonance, Q factor & bandwidth worksheet with answers
1.Easy
f0 = 10 kHzBW = 100 Hz
Q =
2.Easy
A 47 nF capacitor charged to 3 V is switched across an ideal 22 µH inductor. Find the peak current Imax in the circuit, in mA.
C = 47 nFV0 = 3 VL = 22 µH
Imax = mA
3.Medium
A series RLC circuit has R = 1 Ω, L = 10 µH and C = 47 nF. Find its bandwidth BW in kHz.
R = 1 ΩL = 10 µHC = 47 nF
BW = kHz
4.Medium
A series RLC circuit resonates at 2 kHz with Q = 3. Find the lower half-power frequency f1 exactly, in kHz.
f0 = 2 kHzQ = 3
f1 = kHz
5.Hard
The half-power frequencies of a resonance curve are 50 kHz and 62.5 kHz. Find the resonance frequency as their geometric mean, and then the quality factor Q.
f1 = 50 kHzf2 = 62.5 kHz
Q =
6.Hard
A series resonant circuit uses a 100 µH inductor. Which total series resistance R gives a bandwidth of 100 kHz?
L = 100 µHBW = 100 kHz
R = Ω
Answer key
- 1. Q = 100
- 2. Imax = 138.7 mA
- 3. BW = 15.92 kHz
- 4. f1 = 1.694 kHz
- 5. Q = 4.472
- 6. R = 62.83 Ω
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