A 470 nF capacitor is charged to 24 V and then connected to an ideal 47 mH inductor. Find the total energy W that swings between them, in µJ.
LC resonance, Q factor & bandwidth worksheet with answers
1.Easy
C = 470 nFV0 = 24 VL = 47 mH
W = µJ
2.Easy
A resonance curve peaks at 2 kHz, and its half-power points are 80 Hz apart. Find the quality factor Q.
f0 = 2 kHzBW = 80 Hz
Q =
3.Medium
A parallel RLC circuit has R = 1 kΩ, L = 10 µH and C = 22 nF. Find its quality factor Q.
R = 1 kΩL = 10 µHC = 22 nF
Q =
4.Medium
A series RLC circuit has R = 10 Ω, L = 100 µH and C = 22 nF. Find its bandwidth BW in kHz.
R = 10 ΩL = 100 µHC = 22 nF
BW = kHz
5.Hard
Design a series RLC filter with a total resistance of 50 Ω, a resonance frequency of 200 kHz and a bandwidth of 8 kHz. Find the capacitance C in nF.
R = 50 Ωf0 = 200 kHzBW = 8 kHz
C = nF
6.Hard
The half-power frequencies of a resonance curve are 400 kHz and 480 kHz. Find the resonance frequency as their geometric mean, and then the quality factor Q.
f1 = 400 kHzf2 = 480 kHz
Q =
Answer key
- 1. W = 135.4 µJ
- 2. Q = 25
- 3. Q = 46.9
- 4. BW = 15.92 kHz
- 5. C = 0.6366 nF
- 6. Q = 5.477
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