A 470 nF capacitor charged to 9 V is switched across an ideal 10 mH inductor. Find the peak current Imax in the circuit, in mA.
LC resonance, Q factor & bandwidth worksheet with answers
1.Easy
C = 470 nFV0 = 9 VL = 10 mH
Imax = mA
2.Easy
A resonance curve peaks at 2 kHz, and its half-power points are 50 Hz apart. Find the quality factor Q.
f0 = 2 kHzBW = 50 Hz
Q =
3.Medium
A series RLC circuit resonates at 20 kHz with Q = 1.5. Find the lower half-power frequency f1 exactly, in kHz.
f0 = 20 kHzQ = 1.5
f1 = kHz
4.Medium
A 100 nF capacitor charged to 10 V oscillates with an ideal 2.2 mH inductor. Find the energy WL stored in the inductor at the moment the capacitor voltage is 6 V, in µJ.
C = 100 nFV0 = 10 VvC = 6 V
WL = µJ
5.Hard
Design a series RLC filter with a total resistance of 20 Ω, a resonance frequency of 10 kHz and a bandwidth of 1 kHz. Find the capacitance C in nF.
R = 20 Ωf0 = 10 kHzBW = 1 kHz
C = nF
6.Hard
A series resonant circuit uses a 100 mH inductor. Which total series resistance R gives a bandwidth of 1 kHz?
L = 100 mHBW = 1 kHz
R = Ω
Answer key
- 1. Imax = 61.7 mA
- 2. Q = 40
- 3. f1 = 14.42 kHz
- 4. WL = 3.2 µJ
- 5. C = 79.58 nF
- 6. R = 628.3 Ω
Full step-by-step solutions: practise this topic on examproblems.com.