A resonance curve peaks at 500 kHz, and its half-power points are 10 kHz apart. Find the quality factor Q.
LC resonance, Q factor & bandwidth worksheet with answers
A 22 nF capacitor is charged to 3 V and then connected to an ideal 10 µH inductor. Find the total energy W that swings between them, in nJ.
A series RLC circuit resonates at 5 kHz with Q = 2.5. Find the lower half-power frequency f1 exactly, in kHz.
In an ideal LC circuit with L = 0.47 µH and C = 1 µF, the capacitor is fully charged at t = 0. How long does it take until all the energy is in the inductor? Give t in µs.
A charged 47 nF capacitor discharges through a 47 µH coil with a total series resistance of 0.5 Ω, so the oscillation slowly dies out. Its amplitude decays as e−Rt/(2L). How many oscillation cycles n pass before the amplitude has halved? (The losses are small, so the frequency is f₀.)
The half-power frequencies of a resonance curve are 50 kHz and 55 kHz. Find the resonance frequency as their geometric mean, and then the quality factor Q.
Answer key
- 1. Q = 50
- 2. W = 99 nJ
- 3. f1 = 4.099 kHz
- 4. t = 1.077 µs
- 5. n = 13.95
- 6. Q = 10.49
Full step-by-step solutions: practise this topic on examproblems.com.