Magnetic fields & induction worksheet with answers

Free printable Magnetic fields & induction worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

For teachers: free to print, copy and use in class. Every new worksheet has new values and its own answer key. A link to ExamProblems on your course page is appreciated.

Name: ____________________   Date: ____________

1.Easy
nB60°10 cm × 10 cmB = 0.2 T

A rectangular loop of 10 cm by 10 cm lies in a uniform magnetic field of 0.2 T. The field lines make an angle of 30° with the plane of the loop. Find the magnetic flux Φ through the loop.

B = 0.2 TA = 10 cm × 10 cm30° to the plane
Φ = mWb
2.Easy
B0.1 T8 A90°L = 25 cm

A straight wire 25 cm long carries 8 A at an angle of 90° to a uniform magnetic field of 0.1 T. Find the magnitude of the force F on the wire.

B = 0.1 TI = 8 AL = 25 cmθ = 90°
F = N
3.Medium
+vBF = ?

A proton moves down the page through a uniform magnetic field pointing into the page. Click the direction of the magnetic force on it.

v: down the pageB: into the page
  1. 1up the page
  2. 2to the right
  3. 3down the page
  4. 4to the left
4.Medium
−v = 2 × 10⁶ m/sr = ?B = 10 mT

An electron moves at 2 × 10⁶ m/s perpendicular to a uniform magnetic field of 10 mT. Find the radius r of its circular path.

m = 9.109 × 10⁻³¹ kg|q| = 1.602 × 10⁻¹⁹ Cv = 2 × 10⁶ m/sB = 10 mT
r = cm
5.Hard
Bn = 900 rpm10 cm × 5 cmN = 100B = 0.4 T

A coil of 100 turns, 10 cm × 5 cm, rotates at 900 rpm in a uniform field of 0.4 T about an axis perpendicular to the field. Find the rms value Erms of the emf.

N = 100A = 10 cm × 5 cmB = 0.4 Tn = 900 rpm
Erms = V
6.Hard
L = 200 mH0 → 2 A

The current in a 200 mH inductor changes steadily from 0 A to 2 A in 1 ms. Find the magnitude of the self-induced emf ε.

L = 200 mH0 A → 2 AΔt = 1 ms
ε = V

Answer key

  1. 1. Φ = 1 mWb
  2. 2. F = 0.2 N
  3. 3. to the right
  4. 4. r = 0.1137 cm
  5. 5. Erms = 13.33 V
  6. 6. ε = 400 V

Full step-by-step solutions: practise this topic on examproblems.com.