Mechanical vibrations worksheet with answers

Free printable Mechanical vibrations worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 20 kN/mm = 12 kgx

A 12 kg mass hangs from a spring with a stiffness of 20 kN/m. Ignore damping. Find the natural frequency fn in Hz.

m = 12 kgk = 20 kN/m
fn = Hz
2.Easy
k = 12 kN/mm = 10 kgx

A 10 kg mass hangs from a spring with a stiffness of 12 kN/m. Ignore damping. Find the natural circular frequency ωn in rad/s.

m = 10 kgk = 12 kN/m
ωn = rad/s
3.Medium
k = 200 kN/mζ = 0.45m = 20 kg

A 20 kg mass on a spring with a stiffness of 200 kN/m has a viscous damper giving a damping ratio of 0.45. Find the damped natural frequency fd of its free vibration in Hz.

m = 20 kgk = 200 kN/mζ = 0.45
fd = Hz
4.Medium
k = 200 kN/mc = 150 N·s/mm = 12 kg

A 12 kg mass is supported by a spring with a stiffness of 200 kN/m and a viscous damper with a damping coefficient of 150 N·s/m. Find the damping ratio ζ.

m = 12 kgk = 200 kN/mc = 150 N·s/m
ζ =
5.Hard
k1​ = 40k2​ = 5m = 50 kg

A 50 kg mass hangs from two springs side by side (in parallel), with stiffnesses k₁ = 40 kN/m and k₂ = 5 kN/m. The mass stays level. Find the equivalent stiffness keq of the spring system in kN/m.

m = 50 kgk1 = 40 kN/mk2 = 5 kN/m
keq = kN/m
6.Hard
k1​ = 5k2​ = 30m = 5 kg

A 5 kg mass hangs from two springs connected end to end (in series): the upper spring has k₁ = 5 kN/m and the lower one k₂ = 30 kN/m. Find the equivalent stiffness keq of the spring system in kN/m.

m = 5 kgk1 = 5 kN/mk2 = 30 kN/m
keq = kN/m

Answer key

  1. 1. fn = 6.497 Hz
  2. 2. ωn = 34.64 rad/s
  3. 3. fd = 14.21 Hz
  4. 4. ζ = 0.04841
  5. 5. keq = 45 kN/m
  6. 6. keq = 4.286 kN/m

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