Mechanical vibrations worksheet with answers

Free printable Mechanical vibrations worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 80 kN/mm = 15 kgx

A 15 kg mass hangs from a spring with a stiffness of 80 kN/m. Ignore damping. Find the natural circular frequency ωn in rad/s.

m = 15 kgk = 80 kN/m
ωn = rad/s
2.Easy
k = 5 kN/mm = 15 kgx

A 15 kg mass hangs from a spring with a stiffness of 5 kN/m. Ignore damping. Find the natural circular frequency ωn in rad/s.

m = 15 kgk = 5 kN/m
ωn = rad/s
3.Medium
tx40 mm3 cycles18.8 mm

In a free-vibration test of a damped mass–spring system, a displacement peak of 40 mm is followed 3 cycles later by a peak of 18.8 mm. Find the damping ratio ζ.

x0 = 40 mmx3 = 18.8 mmn = 3
ζ =
4.Medium
k = 25 kN/mζ = 0.45m = 12 kg

A 12 kg mass on a spring with a stiffness of 25 kN/m has a viscous damper giving a damping ratio of 0.45. Find the damped natural frequency fd of its free vibration in Hz.

m = 12 kgk = 25 kN/mζ = 0.45
fd = Hz
5.Hard
k1​ = 20k2​ = 15k3​ = 40m = 5 kg

A 5 kg mass hangs from spring k₃ = 40 kN/m. The top of k₃ is attached to a rigid bar that hangs from two springs side by side, k₁ = 20 kN/m and k₂ = 15 kN/m; the bar stays level. Ignore damping and the masses of the springs and bar. Find the natural frequency fn of vertical vibration in Hz.

m = 5 kgk1 = 20 kN/mk2 = 15 kN/mk3 = 40 kN/m
fn = Hz
6.Hard
k1​ = 20k2​ = 60m = 40 kg

A 40 kg mass hangs from two springs side by side (in parallel), with stiffnesses k₁ = 20 kN/m and k₂ = 60 kN/m. The mass stays level. Find the equivalent stiffness keq of the spring system in kN/m.

m = 40 kgk1 = 20 kN/mk2 = 60 kN/m
keq = kN/m

Answer key

  1. 1. ωn = 73.03 rad/s
  2. 2. ωn = 18.26 rad/s
  3. 3. ζ = 0.04002
  4. 4. fd = 6.487 Hz
  5. 5. fn = 9.725 Hz
  6. 6. keq = 80 kN/m

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