Mechanical vibrations worksheet with answers

Free printable Mechanical vibrations worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
kmδst​ = 4 mmunloaded

A machine rests on spring mounts, which compress by 4 mm under its weight. Treat it as an undamped single-degree-of-freedom system and use g = 9.81 m/s². Find the natural frequency fn of vertical vibration in Hz.

δst = 4 mmg = 9.81 m/s²
fn = Hz
2.Easy
k = 4 kN/mm = 12 kgx

A 12 kg mass hangs from a spring with a stiffness of 4 kN/m. Ignore damping. Find the natural circular frequency ωn in rad/s.

m = 12 kgk = 4 kN/m
ωn = rad/s
3.Medium
k = 15 kN/mc = 200 N·s/mm = 100 kg

A 100 kg mass is supported by a spring with a stiffness of 15 kN/m and a viscous damper with a damping coefficient of 200 N·s/m. Find the damping ratio ζ.

m = 100 kgk = 15 kN/mc = 200 N·s/m
ζ =
4.Medium
k = 12 kN/mζ = 0.45m = 10 kg

A 10 kg mass on a spring with a stiffness of 12 kN/m has a viscous damper giving a damping ratio of 0.45. Find the damped natural frequency fd of its free vibration in Hz.

m = 10 kgk = 12 kN/mζ = 0.45
fd = Hz
5.Hard
k1​ = 30k2​ = 100m = 50 kg

A 50 kg mass hangs from two springs side by side (in parallel), with stiffnesses k₁ = 30 kN/m and k₂ = 100 kN/m. The mass stays level. Find the equivalent stiffness keq of the spring system in kN/m.

m = 50 kgk1 = 30 kN/mk2 = 100 kN/m
keq = kN/m
6.Hard
k1​ = 80k2​ = 30m = 20 kg

A 20 kg mass hangs from two springs side by side (in parallel), with stiffnesses k₁ = 80 kN/m and k₂ = 30 kN/m. The mass stays level. Find the equivalent stiffness keq of the spring system in kN/m.

m = 20 kgk1 = 80 kN/mk2 = 30 kN/m
keq = kN/m

Answer key

  1. 1. fn = 7.882 Hz
  2. 2. ωn = 18.26 rad/s
  3. 3. ζ = 0.08165
  4. 4. fd = 4.924 Hz
  5. 5. keq = 130 kN/m
  6. 6. keq = 110 kN/m

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