Mechanical vibrations worksheet with answers

Free printable Mechanical vibrations worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 200 kN/mm = 150 kgx

A 150 kg mass hangs from a spring with a stiffness of 200 kN/m. Ignore damping. Find the natural frequency fn in Hz.

m = 150 kgk = 200 kN/m
fn = Hz
2.Easy
k = 20 kN/mm = 150 kgx

A 150 kg mass hangs from a spring with a stiffness of 20 kN/m. Ignore damping. Find the natural frequency fn in Hz.

m = 150 kgk = 20 kN/m
fn = Hz
3.Medium
tx15 mm2 cycles9.1 mm

In a free-vibration test of a damped mass–spring system, a displacement peak of 15 mm is followed 2 cycles later by a peak of 9.1 mm. Find the damping ratio ζ.

x0 = 15 mmx2 = 9.1 mmn = 2
ζ =
4.Medium
k = 15 kN/mζ = 0.35m = 100 kg

A 100 kg mass on a spring with a stiffness of 15 kN/m has a viscous damper giving a damping ratio of 0.35. Find the damped natural frequency fd of its free vibration in Hz.

m = 100 kgk = 15 kN/mζ = 0.35
fd = Hz
5.Hard
k1​ = 50k2​ = 80k3​ = 60m = 100 kg

A 100 kg mass hangs from spring k₃ = 60 kN/m. The top of k₃ is attached to a rigid bar that hangs from two springs side by side, k₁ = 50 kN/m and k₂ = 80 kN/m; the bar stays level. Ignore damping and the masses of the springs and bar. Find the natural frequency fn of vertical vibration in Hz.

m = 100 kgk1 = 50 kN/mk2 = 80 kN/mk3 = 60 kN/m
fn = Hz
6.Hard
k1​ = 10k2​ = 100m = 10 kg

A 10 kg mass hangs from two springs side by side (in parallel), with stiffnesses k₁ = 10 kN/m and k₂ = 100 kN/m. The mass stays level. Find the equivalent stiffness keq of the spring system in kN/m.

m = 10 kgk1 = 10 kN/mk2 = 100 kN/m
keq = kN/m

Answer key

  1. 1. fn = 5.812 Hz
  2. 2. fn = 1.838 Hz
  3. 3. ζ = 0.03974
  4. 4. fd = 1.826 Hz
  5. 5. fn = 3.225 Hz
  6. 6. keq = 110 kN/m

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