Mechanical vibrations worksheet with answers

Free printable Mechanical vibrations worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 80 kN/mm = 80 kgx

An 80 kg mass hangs from a spring with a stiffness of 80 kN/m. Ignore damping. Find the natural circular frequency ωn in rad/s.

m = 80 kgk = 80 kN/m
ωn = rad/s
2.Easy
k = 100 kN/mm = 200 kgx

A 200 kg mass hangs from a spring with a stiffness of 100 kN/m. Ignore damping. Find the natural frequency fn in Hz.

m = 200 kgk = 100 kN/m
fn = Hz
3.Medium
k = 20 kN/mζ = 0.7m = 200 kg

A 200 kg mass on a spring with a stiffness of 20 kN/m has a viscous damper giving a damping ratio of 0.7. Find the damped natural frequency fd of its free vibration in Hz.

m = 200 kgk = 20 kN/mζ = 0.7
fd = Hz
4.Medium
k = 20 kN/mc = 760 N·s/mm = 20 kg

A 20 kg mass is supported by a spring with a stiffness of 20 kN/m and a viscous damper with a damping coefficient of 760 N·s/m. Find the damping ratio ζ.

m = 20 kgk = 20 kN/mc = 760 N·s/m
ζ =
5.Hard
k1​ = 20k2​ = 40m = 25 kg

A 25 kg mass hangs from two springs connected end to end (in series): the upper spring has k₁ = 20 kN/m and the lower one k₂ = 40 kN/m. Find the equivalent stiffness keq of the spring system in kN/m.

m = 25 kgk1 = 20 kN/mk2 = 40 kN/m
keq = kN/m
6.Hard
k1​ = 100k2​ = 25m = 10 kg

A 10 kg mass hangs from two springs connected end to end (in series): the upper spring has k₁ = 100 kN/m and the lower one k₂ = 25 kN/m. Find the equivalent stiffness keq of the spring system in kN/m.

m = 10 kgk1 = 100 kN/mk2 = 25 kN/m
keq = kN/m

Answer key

  1. 1. ωn = 31.62 rad/s
  2. 2. fn = 3.559 Hz
  3. 3. fd = 1.137 Hz
  4. 4. ζ = 0.6008
  5. 5. keq = 13.33 kN/m
  6. 6. keq = 20 kN/m

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