Mechanical vibrations worksheet with answers

Free printable Mechanical vibrations worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
k = 5 kN/mm = 8 kgx

An 8 kg mass hangs from a spring with a stiffness of 5 kN/m. Ignore damping. Find the natural circular frequency ωn in rad/s.

m = 8 kgk = 5 kN/m
ωn = rad/s
2.Easy
kmδst​ = 4 mmunloaded

A machine rests on spring mounts, which compress by 4 mm under its weight. Treat it as an undamped single-degree-of-freedom system and use g = 9.81 m/s². Find the natural frequency fn of vertical vibration in Hz.

δst = 4 mmg = 9.81 m/s²
fn = Hz
3.Medium
k = 80 kN/mc = 90 N·s/mm = 10 kg

A 10 kg mass is supported by a spring with a stiffness of 80 kN/m and a viscous damper with a damping coefficient of 90 N·s/m. Find the damping ratio ζ.

m = 10 kgk = 80 kN/mc = 90 N·s/m
ζ =
4.Medium
tx15 mm1 cycle12.4 mm

In a free-vibration test of a damped mass–spring system, a displacement peak of 15 mm is followed one cycle later by a peak of 12.4 mm. Find the damping ratio ζ.

x0 = 15 mmx1 = 12.4 mmn = 1
ζ =
5.Hard
k1​ = 50k2​ = 80m = 100 kg

A 100 kg mass hangs from two springs connected end to end (in series): the upper spring has k₁ = 50 kN/m and the lower one k₂ = 80 kN/m. Ignore damping and the masses of the springs. Find the natural frequency fn of vertical vibration in Hz.

m = 100 kgk1 = 50 kN/mk2 = 80 kN/m
fn = Hz
6.Hard
k1​ = 5k2​ = 15m = 40 kg

A 40 kg mass hangs from two springs side by side (in parallel), with stiffnesses k₁ = 5 kN/m and k₂ = 15 kN/m. The mass stays level. Find the equivalent stiffness keq of the spring system in kN/m.

m = 40 kgk1 = 5 kN/mk2 = 15 kN/m
keq = kN/m

Answer key

  1. 1. ωn = 25 rad/s
  2. 2. fn = 7.882 Hz
  3. 3. ζ = 0.05031
  4. 4. ζ = 0.03028
  5. 5. fn = 2.792 Hz
  6. 6. keq = 20 kN/m

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