Mechanical vibrations worksheet with answers

Free printable Mechanical vibrations worksheet: 6 problems from easy to exam level, with an answer key. Print it or save it as a PDF.

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1.Easy
kmδst​ = 5 mmunloaded

A machine rests on spring mounts, which compress by 5 mm under its weight. Treat it as an undamped single-degree-of-freedom system and use g = 9.81 m/s². Find the natural frequency fn of vertical vibration in Hz.

δst = 5 mmg = 9.81 m/s²
fn = Hz
2.Easy
k = 25 kN/mm = 5 kgx

A 5 kg mass hangs from a spring with a stiffness of 25 kN/m. Ignore damping. Find the natural circular frequency ωn in rad/s.

m = 5 kgk = 25 kN/m
ωn = rad/s
3.Medium
k = 10 kN/mc = 270 N·s/mm = 5 kg

A 5 kg mass is supported by a spring with a stiffness of 10 kN/m and a viscous damper with a damping coefficient of 270 N·s/m. Find the damping ratio ζ.

m = 5 kgk = 10 kN/mc = 270 N·s/m
ζ =
4.Medium
k = 20 kN/mc = 660 N·s/mm = 15 kg

A 15 kg mass is supported by a spring with a stiffness of 20 kN/m and a viscous damper with a damping coefficient of 660 N·s/m. Find the damping ratio ζ.

m = 15 kgk = 20 kN/mc = 660 N·s/m
ζ =
5.Hard
k1​ = 5k2​ = 15m = 5 kg

A 5 kg mass hangs from two springs connected end to end (in series): the upper spring has k₁ = 5 kN/m and the lower one k₂ = 15 kN/m. Find the equivalent stiffness keq of the spring system in kN/m.

m = 5 kgk1 = 5 kN/mk2 = 15 kN/m
keq = kN/m
6.Hard
k1​ = 40k2​ = 15m = 20 kg

A 20 kg mass hangs from two springs side by side (in parallel), with stiffnesses k₁ = 40 kN/m and k₂ = 15 kN/m. The mass stays level. Find the equivalent stiffness keq of the spring system in kN/m.

m = 20 kgk1 = 40 kN/mk2 = 15 kN/m
keq = kN/m

Answer key

  1. 1. fn = 7.05 Hz
  2. 2. ωn = 70.71 rad/s
  3. 3. ζ = 0.6037
  4. 4. ζ = 0.6025
  5. 5. keq = 3.75 kN/m
  6. 6. keq = 55 kN/m

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