A point in a loaded part has σₓ = 140 MPa, σᵧ = 120 MPa and τₓᵧ = −30 MPa (tension positive). Find the smallest principal stress σ2.
Mohr’s circle & stress transformation worksheet with answers
A point in a loaded part has σₓ = 20 MPa, σᵧ = −40 MPa and τₓᵧ = −40 MPa (tension positive). Find the largest principal stress σ1.
A point has σₓ = 140 MPa, σᵧ = 10 MPa and τₓᵧ = −60 MPa (tension positive). The element is rotated 20° counter-clockwise. Find the normal stress σy′ on the faces of the rotated element that are perpendicular to the rotated y′-axis.
A point has σₓ = 160 MPa, σᵧ = 100 MPa and τₓᵧ = 20 MPa (tension positive). Find the angle θs, between −90° and 90°, from the x-axis to the normal of the plane on which the shear stress has its maximum positive value +R (shear positive in the same sense as τₓᵧ).
A point in a loaded part has σₓ = 0 MPa, σᵧ = 110 MPa and τₓᵧ = 50 MPa (tension positive). Find the shear stress τθ on a plane whose normal is rotated 30° counter-clockwise from the x-axis (positive in the same sense as τₓᵧ).
A point in a thin plate is in plane stress: σₓ = 120 MPa, σᵧ = 70 MPa and τₓᵧ = 30 MPa (σz = 0). The material has a yield strength of 420 MPa. Find the factor of safety n against yielding by the Tresca (maximum shear stress) criterion.
Answer key
- 1. σ2 = 98.38 MPa
- 2. σ1 = 40 MPa
- 3. σy′ = 63.77 MPa
- 4. θs = −28.15 °
- 5. τθ = 72.63 MPa
- 6. n = 3.133
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