A point in a loaded part has σₓ = 120 MPa, σᵧ = −30 MPa and τₓᵧ = 60 MPa (tension positive). Find the smallest principal stress σ2.
Mohr’s circle & stress transformation worksheet with answers
A point in a loaded part has σₓ = −80 MPa, σᵧ = −40 MPa and τₓᵧ = 10 MPa (tension positive). Find the largest principal stress σ1.
A point in a thin plate is in plane stress: σₓ = 90 MPa, σᵧ = 100 MPa and τₓᵧ = 30 MPa, with σz = 0. Find the absolute maximum shear stress τabs at the point (considering all planes in three dimensions).
A point in a loaded part has σₓ = 90 MPa, σᵧ = 120 MPa and τₓᵧ = 40 MPa (tension positive). Find the angle θp from the x-axis to the direction of the largest principal stress, between −90° and 90°.
A point in a thin plate is in plane stress: σₓ = 140 MPa, σᵧ = −10 MPa and τₓᵧ = −40 MPa (σz = 0). The material has a yield strength of 300 MPa. Find the factor of safety n against yielding by the Tresca (maximum shear stress) criterion.
A point in a loaded part has σₓ = 80 MPa, σᵧ = 60 MPa and τₓᵧ = −20 MPa (tension positive). Find the shear stress τθ on a plane whose normal is rotated 20° clockwise from the x-axis (positive in the same sense as τₓᵧ).
Answer key
- 1. σ2 = −51.05 MPa
- 2. σ1 = −37.64 MPa
- 3. τabs = 62.71 MPa
- 4. θp = 55.28 °
- 5. n = 1.765
- 6. τθ = −8.893 MPa
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