At a point in a loaded part the in-plane principal stresses are σ₁ = 70 MPa and σ₂ = 20 MPa (tension positive). Find the normal stress σavg that acts on the planes of maximum in-plane shear stress.
Mohr’s circle & stress transformation worksheet with answers
A point has σₓ = −50 MPa and σᵧ = 40 MPa, plus some shear stress. On an element rotated by 25° the normal stress in the rotated x′ direction is −26.3 MPa. Find the normal stress σy′ in the rotated y′ direction.
A point has σₓ = −60 MPa, σᵧ = 80 MPa and τₓᵧ = 30 MPa (tension positive). The element is rotated 25° counter-clockwise. Find the normal stress σy′ on the faces of the rotated element that are perpendicular to the rotated y′-axis.
A point in a loaded part has σₓ = −70 MPa, σᵧ = 20 MPa and τₓᵧ = −50 MPa (tension positive). Find the angle θp from the x-axis to the direction of the largest principal stress, between −90° and 90°.
A point in a loaded part has σₓ = 0 MPa, σᵧ = 70 MPa and τₓᵧ = 60 MPa (tension positive). Find the normal stress σθ on a plane whose normal is rotated 25° counter-clockwise from the x-axis.
A point in a thin plate is in plane stress: σₓ = −20 MPa, σᵧ = −80 MPa and τₓᵧ = −60 MPa (σz = 0). The material has a yield strength of 250 MPa. Find the factor of safety n against yielding by the Tresca (maximum shear stress) criterion.
Answer key
- 1. σavg = 45 MPa
- 2. σy′ = 16.3 MPa
- 3. σy′ = 32.01 MPa
- 4. θp = −65.99 °
- 5. σθ = 58.47 MPa
- 6. n = 1.863
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