A point in a loaded part has σₓ = −70 MPa, σᵧ = 40 MPa and τₓᵧ = 60 MPa (tension positive). Find the smallest principal stress σ2.
Mohr’s circle & stress transformation worksheet with answers
A point on the surface of a shaft in torsion is in pure shear with τₓᵧ = −60 MPa (σₓ = σᵧ = 0). Find the normal stress σθ on a plane whose normal is rotated 35° counter-clockwise from the x-axis.
A point has σₓ = 130 MPa, σᵧ = −10 MPa and τₓᵧ = 40 MPa (tension positive). Find the angle θs, between −90° and 90°, from the x-axis to the normal of the plane on which the shear stress has its maximum positive value +R (shear positive in the same sense as τₓᵧ).
A point in a loaded part has σₓ = −60 MPa, σᵧ = 80 MPa and τₓᵧ = 50 MPa (tension positive). Find the maximum in-plane shear stress τmax.
A solid shaft of diameter 30 mm carries a bending moment of 500 N·m together with a torque of 1000 N·m. At the top surface, where the bending stress is tensile and largest, find the largest principal stress σ1.
A point in a loaded part has σₓ = 10 MPa, σᵧ = 20 MPa and τₓᵧ = 20 MPa (tension positive). Find the normal stress σθ on a plane whose normal is rotated 15° counter-clockwise from the x-axis.
Answer key
- 1. σ2 = −96.39 MPa
- 2. σθ = −56.38 MPa
- 3. θs = −30.13 °
- 4. τmax = 86.02 MPa
- 5. σ1 = 305.2 MPa
- 6. σθ = 20.67 MPa
Full step-by-step solutions: practise this topic on examproblems.com.