A point in a loaded part has σₓ = 50 MPa, σᵧ = −30 MPa and τₓᵧ = −20 MPa (tension positive). Find the smallest principal stress σ2.
Mohr’s circle & stress transformation worksheet with answers
At a point in a loaded part the in-plane principal stresses are σ₁ = 200 MPa and σ₂ = −110 MPa (tension positive). Find the normal stress σavg that acts on the planes of maximum in-plane shear stress.
A point has σₓ = −10 MPa and σᵧ = 10 MPa. How large can the shear stress τxy (magnitude) become before the largest principal stress reaches 50 MPa?
A point in a thin plate is in plane stress: σₓ = 150 MPa, σᵧ = 60 MPa and τₓᵧ = −50 MPa, with σz = 0. Find the absolute maximum shear stress τabs at the point (considering all planes in three dimensions).
A point in a thin plate is in plane stress: σₓ = 130 MPa, σᵧ = −30 MPa and τₓᵧ = −20 MPa (σz = 0). Find the von Mises equivalent stress σvM.
A point in a thin plate is in plane stress: σₓ = 100 MPa, σᵧ = 110 MPa and τₓᵧ = −60 MPa (σz = 0). The material has a yield strength of 420 MPa. Find the factor of safety n against yielding by the Tresca (maximum shear stress) criterion.
Answer key
- 1. σ2 = −34.72 MPa
- 2. σavg = 45 MPa
- 3. τxy = 48.99 MPa
- 4. τabs = 86.13 MPa
- 5. σvM = 151.3 MPa
- 6. n = 2.542
Full step-by-step solutions: practise this topic on examproblems.com.