A point in a loaded part has σₓ = −40 MPa, σᵧ = 100 MPa and τₓᵧ = 20 MPa (tension positive). Find the smallest principal stress σ2.
Mohr’s circle & stress transformation worksheet with answers
A point has σₓ = 70 MPa and σᵧ = 10 MPa, plus some shear stress. On an element rotated by 20° the normal stress in the rotated x′ direction is 50.1 MPa. Find the normal stress σy′ in the rotated y′ direction.
A point has σₓ = −40 MPa and σᵧ = −30 MPa. How large can the shear stress τxy (magnitude) become before the largest principal stress reaches −15 MPa?
A point has σₓ = 70 MPa, σᵧ = 40 MPa and τₓᵧ = 40 MPa (tension positive). The element is rotated 25° counter-clockwise. Find the normal stress σy′ on the faces of the rotated element that are perpendicular to the rotated y′-axis.
A point in a thin plate is in plane stress: σₓ = −50 MPa, σᵧ = 80 MPa and τₓᵧ = 50 MPa (σz = 0). The material has a yield strength of 300 MPa. Find the factor of safety n against yielding by the Tresca (maximum shear stress) criterion.
A point in a loaded part has σₓ = −50 MPa, σᵧ = −20 MPa and τₓᵧ = 60 MPa (tension positive). Find the shear stress τθ on a plane whose normal is rotated 45° counter-clockwise from the x-axis (positive in the same sense as τₓᵧ).
Answer key
- 1. σ2 = −42.8 MPa
- 2. σy′ = 29.9 MPa
- 3. τxy = 19.36 MPa
- 4. σy′ = 14.72 MPa
- 5. n = 1.829
- 6. τθ = 15 MPa
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