What mass m of C6H12O6 (M = 180.16 g/mol) do you need to make 500 mL of a 0.2 mol/L solution?
Molarity & dilution worksheet with answers
1.Easy
V = 500 mLc = 0.2 mol/LM = 180.16 g/mol
m = g
2.Easy
What mass m of Na2CO3 (M = 105.99 g/mol) do you need to make 500 mL of a 0.25 mol/L solution?
V = 500 mLc = 0.25 mol/LM = 105.99 g/mol
m = g
3.Medium
You need 200 mL of 0.25 mol/L solution and have a 1 mol/L stock solution. What volume V1 of stock solution do you need?
c1 = 1 mol/Lc2 = 0.25 mol/LV2 = 200 mL
V1 = mL
4.Medium
You need 1000 mL of 0.4 mol/L solution and have a 3 mol/L stock solution. What volume V1 of stock solution do you need?
c1 = 3 mol/Lc2 = 0.4 mol/LV2 = 1000 mL
V1 = mL
5.Hard
250 mL of a 0.8 mol/L solution is mixed with 100 mL of a 1.2 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 0.8 mol/LV1 = 250 mLc2 = 1.2 mol/LV2 = 100 mL
c = mol/L
6.Hard
150 mL of a 1 mol/L solution is mixed with 400 mL of a 1.2 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 1 mol/LV1 = 150 mLc2 = 1.2 mol/LV2 = 400 mL
c = mol/L
Answer key
- 1. m = 18.02 g
- 2. m = 13.25 g
- 3. V1 = 50 mL
- 4. V1 = 133.3 mL
- 5. c = 0.9143 mol/L
- 6. c = 1.145 mol/L
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