19 g of KNO3 (M = 101.1 g/mol) is dissolved in water to make 500 mL of solution. Find the molarity c.
Molarity & dilution worksheet with answers
1.Easy
m = 19 gM = 101.1 g/molV = 500 mL
c = mol/L
2.Easy
What mass m of KMnO4 (M = 158.03 g/mol) do you need to make 500 mL of a 0.25 mol/L solution?
V = 500 mLc = 0.25 mol/LM = 158.03 g/mol
m = g
3.Medium
You need 100 mL of 0.25 mol/L solution and have a 3 mol/L stock solution. How much water Vwater do you add to the stock solution?
c1 = 3 mol/Lc2 = 0.25 mol/LV2 = 100 mL
Vwater = mL
4.Medium
You need 500 mL of 0.4 mol/L solution and have a 3 mol/L stock solution. What volume V1 of stock solution do you need?
c1 = 3 mol/Lc2 = 0.4 mol/LV2 = 500 mL
V1 = mL
5.Hard
150 mL of a 1 mol/L solution is mixed with 400 mL of a 0.05 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 1 mol/LV1 = 150 mLc2 = 0.05 mol/LV2 = 400 mL
c = mol/L
6.Hard
300 mL of a 2 mol/L solution is mixed with 100 mL of a 0.05 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 2 mol/LV1 = 300 mLc2 = 0.05 mol/LV2 = 100 mL
c = mol/L
Answer key
- 1. c = 0.3759 mol/L
- 2. m = 19.75 g
- 3. Vwater = 91.67 mL
- 4. V1 = 66.67 mL
- 5. c = 0.3091 mol/L
- 6. c = 1.512 mol/L
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