What mass m of NaCl (M = 58.44 g/mol) do you need to make 200 mL of a 0.25 mol/L solution?
Molarity & dilution worksheet with answers
1.Easy
V = 200 mLc = 0.25 mol/LM = 58.44 g/mol
m = g
2.Easy
23 g of CaCl2 (M = 110.98 g/mol) is dissolved in water to make 750 mL of solution. Find the molarity c.
m = 23 gM = 110.98 g/molV = 750 mL
c = mol/L
3.Medium
You need 250 mL of 0.3 mol/L solution and have a 5 mol/L stock solution. How much water Vwater do you add to the stock solution?
c1 = 5 mol/Lc2 = 0.3 mol/LV2 = 250 mL
Vwater = mL
4.Medium
You need 500 mL of 0.5 mol/L solution and have a 5 mol/L stock solution. What volume V1 of stock solution do you need?
c1 = 5 mol/Lc2 = 0.5 mol/LV2 = 500 mL
V1 = mL
5.Hard
100 mL of a 0.2 mol/L solution is mixed with 50 mL of a 0.3 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 0.2 mol/LV1 = 100 mLc2 = 0.3 mol/LV2 = 50 mL
c = mol/L
6.Hard
250 mL of a 1 mol/L solution is mixed with 400 mL of a 2.5 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 1 mol/LV1 = 250 mLc2 = 2.5 mol/LV2 = 400 mL
c = mol/L
Answer key
- 1. m = 2.922 g
- 2. c = 0.2763 mol/L
- 3. Vwater = 235 mL
- 4. V1 = 50 mL
- 5. c = 0.2333 mol/L
- 6. c = 1.923 mol/L
Full step-by-step solutions: practise this topic on examproblems.com.