What mass m of KCl (M = 74.55 g/mol) do you need to make 250 mL of a 0.15 mol/L solution?
Molarity & dilution worksheet with answers
1.Easy
V = 250 mLc = 0.15 mol/LM = 74.55 g/mol
m = g
2.Easy
24 g of Na2CO3 (M = 105.99 g/mol) is dissolved in water to make 100 mL of solution. Find the molarity c.
m = 24 gM = 105.99 g/molV = 100 mL
c = mol/L
3.Medium
You need 250 mL of 0.5 mol/L solution and have a 6 mol/L stock solution. What volume V1 of stock solution do you need?
c1 = 6 mol/Lc2 = 0.5 mol/LV2 = 250 mL
V1 = mL
4.Medium
You need 1000 mL of 0.3 mol/L solution and have a 5 mol/L stock solution. What volume V1 of stock solution do you need?
c1 = 5 mol/Lc2 = 0.3 mol/LV2 = 1000 mL
V1 = mL
5.Hard
200 mL of a 0.1 mol/L solution is mixed with 100 mL of a 0.05 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 0.1 mol/LV1 = 200 mLc2 = 0.05 mol/LV2 = 100 mL
c = mol/L
6.Hard
250 mL of a 0.4 mol/L solution is mixed with 500 mL of a 0.05 mol/L solution of the same substance. Find the concentration c of the mixture (volumes are additive).
c1 = 0.4 mol/LV1 = 250 mLc2 = 0.05 mol/LV2 = 500 mL
c = mol/L
Answer key
- 1. m = 2.796 g
- 2. c = 2.264 mol/L
- 3. V1 = 20.83 mL
- 4. V1 = 60 mL
- 5. c = 0.08333 mol/L
- 6. c = 0.1667 mol/L
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